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Note on the Congruence $2^{4n} \equiv (---)^n(2n)!/(n!)^2$, Where 2n + 1 is a Prime

F. Morley
Annals of Mathematics
Vol. 9, No. 1/6 (1894 - 1895), pp. 168-170
Published by: Annals of Mathematics
DOI: 10.2307/1967516
Stable URL: http://www.jstor.org/stable/1967516
Page Count: 3
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Note on the Congruence $2^{4n} \equiv (---)^n(2n)!/(n!)^2$, Where 2n + 1 is a Prime
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